MCA NIMCET Computer Memory Back-up Devices Previous Year Question Paper and Solution with PDF

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MCA NIMCET Previous Year Questions (PYQs)

MCA NIMCET Computer Memory Back-up Devices PYQ

Qus : 1MCA NIMCET PYQ

One TeraByte(TB)=_________GB and One ExaByte(EB)=_______GB

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Solution

Unit	Shortened	Capacity
Bit	b	1 or 0 (on or off)
Byte	B	8 bits
Kilobyte	KB	1024 bytes
Megabyte	MB	1024 kilobytes
Gigabyte	GB	1024 megabytes
Terabyte	TB	1024 gigabytes
Petabyte	PB	1024 terabytes
Exabyte	EB	1024 petabytes
Zettabyte	ZB	1024 exabytes
Yottabyte	YB	1024 zettabytes

Qus : 2MCA NIMCET PYQ

Which of the following is the fastest means of memory access for CPU?

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Solution

Registers are a type of computer memory used to quickly accept, store, and transfer data and instructions that are being used immediately by the CPU. The registers used by the CPU are often termed as Processor registers.

Qus : 3MCA NIMCET PYQ

Let the memory access time is 10 miliseconds and cache hit ratio 15%. The effective memory access time is

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Solution

Qus : 4MCA NIMCET PYQ

Dynamic RAM consumes……. Power and ……than Static RAM

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Solution

Qus : 5MCA NIMCET PYQ

A wrong sentence related to FAT 32 and NTFS file systems is

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Solution

Qus : 6MCA NIMCET PYQ

What is the name of the storage device that compensates the difference in rates of flow of data from one device to another?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2023 PYQ

Solution

Data Flow Management

Question:
What is the name of the storage device that compensates the difference in rates of flow of data from one device to another?

✅ Correct Answer: Buffer

Explanation:

A Buffer is a temporary storage area that helps in matching the speed of data transfer between a fast and a slow device, ensuring smooth data flow without loss.

Final Answer: Buffer

Qus : 7MCA NIMCET PYQ

How many 32K $\times$ 1 RAM chips are needed to provide a memory capacity of 256K bytes?

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Solution

Quick Solution

Each RAM chip: 32K × 1 = 32K bits = 4 KB

Total required: 256 KB

Number of chips needed: 256 ÷ 4 = 64

✅ Final Answer: 64 chips

Qus : 8MCA NIMCET PYQ

Consider a hard disk with 16 recording surfaces (0 – 15) having 16384 cylinders (0 – 16383) and each cylinder contains 64 sectors (0 – 63). Data storage capacity in each sector is 512 bytes. Data are organized stored in the disk and the starting disk location of the file is < 1200, 9, 40>. What is the cylinder number of the last sector of the file, if it is stored in a contiguous manner?

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